y^2+12y=60

Solution for y^2+12y=60 equation:

y^2+12y=60

We move all terms to the left:

y^2+12y-(60)=0

a = 1; b = 12; c = -60;
Δ = b2-4ac
Δ = 122-4·1·(-60)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8\sqrt{6}}{2*1}=\frac{-12-8\sqrt{6}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8\sqrt{6}}{2*1}=\frac{-12+8\sqrt{6}}{2}
$